The animation below shows a semicircle centred at with radius that varies over time. As changes, every labelled point moves — yet two triangles, shaded in blue, remain congruent throughout. This is the central question the video explores: why does congruence persist no matter what is?
The diameter lies flat on the x-axis with centre . Point sits on the large outer semicircle, directly above . Points and are marked on the diameter, symmetric about , so that:
Point lies on a smaller inner arc, also of radius centred at , so:
This gives us three segments of equal length radiating from :
The animation highlights two triangles in blue at every moment:
Triangle — with vertices at , , and .
Triangle — with vertices at , , and .
We claim these two triangles are always congruent. To prove it, we identify three pairs of equal sides.
Step 1 — Two radii per triangle.
Since , , , all lie on circles of radius centred at :
Therefore:
Step 2 — The shared third side.
Both triangles share the segment as their base — or more precisely, and are both equal to , so the base of each triangle measured from is identical.
Step 3 — Applying SSS.
Collecting all three pairs:
By the SSS congruence criterion:
This holds for every value of — which is exactly what the animation makes visible. As the radius grows or shrinks, both triangles scale together, keeping all three side-length equalities intact.
A static diagram can show congruence for one particular radius. The animation goes further: it demonstrates that the proof is independent of . The congruence is not a lucky accident at a specific size — it is a structural consequence of both triangles being built from the same radius of the same circle.
This is a recurring idea in geometry: when multiple lengths are all constrained to equal the same quantity (here, ), congruence is not something you check — it is something you can see.
Notice that and are not assumed equal in this proof. SSS is sufficient on its own — we do not need to invoke any angle relationships.