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Geometry and Trigonometry

Geometry and Trigonometry

Introduction to geometry and trigonometry, exploring shapes, angles, and relationships forming the foundation for spatial reasoning and advanced mathematical problem-solving.

Geometry and Trigonometry

Introduction to geometry and trigonometry, exploring shapes, angles, and relationships forming the foundation for spatial reasoning and advanced mathematical problem-solving.

Linear Equations and Inequalities

4 min read

Concepts of Geometry

4 min read

Angle Relationships

3 min read

Congruence Proof

0:21

Congruence Proof Practice

3 tasks

Points, Lines, Planes

23 min read

Congruence Proof

0:21
Apr 9, 2026
Free
Video Details

The animation below shows a semicircle centred at OOO with radius RRR that varies over time. As RRR changes, every labelled point moves — yet two triangles, shaded in blue, remain congruent throughout. This is the central question the video explores: why does congruence persist no matter what RRR is?

Edit Graph on Desmos

The SetupLink to the-setup

The diameter AB‾\overline{AB}AB lies flat on the x-axis with centre OOO. Point CCC sits on the large outer semicircle, directly above OOO. Points MMM and KKK are marked on the diameter, symmetric about OOO, so that:

OM=OK=rOM = OK = rOM=OK=r

Point LLL lies on a smaller inner arc, also of radius RRR centred at OOO, so:

OL=rOL = rOL=r

This gives us three segments of equal length radiating from OOO:

OM=OC=OK=OL=rOM = OC = OK = OL = rOM=OC=OK=OL=r


The Two TrianglesLink to the-two-triangles

The animation highlights two triangles in blue at every moment:

Triangle △CMO\triangle CMO△CMO — with vertices at CCC, MMM, and OOO.

Triangle △OLK\triangle OLK△OLK — with vertices at OOO, LLL, and KKK.

We claim these two triangles are always congruent. To prove it, we identify three pairs of equal sides.


The ProofLink to the-proof

Step 1 — Two radii per triangle.

Since CCC, MMM, LLL, KKK all lie on circles of radius RRR centred at OOO:

OC=r,OM=r,OL=r,OK=rOC = r, \quad OM = r, \quad OL = r, \quad OK = rOC=r,OM=r,OL=r,OK=r

Therefore:

OC=OK=randOM=OL=rOC = OK = r \qquad \text{and} \qquad OM = OL = rOC=OK=randOM=OL=r

Step 2 — The shared third side.

Both triangles share the segment MK‾\overline{MK}MK as their base — or more precisely, OMOMOM and OKOKOK are both equal to RRR, so the base of each triangle measured from OOO is identical.

Step 3 — Applying SSS.

Collecting all three pairs:

OC=OK=rOC = OK = rOC=OK=r

OM=OL=rOM = OL = rOM=OL=r

CM=LK(follows from the above by the distance formula)CM = LK \quad \text{(follows from the above by the distance formula)}CM=LK(follows from the above by the distance formula)

By the SSS congruence criterion:

△CMO≅△OLK\boxed{\triangle CMO \cong \triangle OLK}△CMO≅△OLK​

This holds for every value of RRR — which is exactly what the animation makes visible. As the radius grows or shrinks, both triangles scale together, keeping all three side-length equalities intact.


Why the Animation MattersLink to why-the-animation-matters

A static diagram can show congruence for one particular radius. The animation goes further: it demonstrates that the proof is independent of RRR. The congruence is not a lucky accident at a specific size — it is a structural consequence of both triangles being built from the same radius of the same circle.

This is a recurring idea in geometry: when multiple lengths are all constrained to equal the same quantity (here, RRR), congruence is not something you check — it is something you can see.

Note

Notice that ∠MOC\angle MOC∠MOC and ∠LOK\angle LOK∠LOK are not assumed equal in this proof. SSS is sufficient on its own — we do not need to invoke any angle relationships.

Chapters

  • –Introduction & Setup
  • –Identifying the Two Triangles
  • –The SSS Proof
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